father age is 3 time the sum of the ages two children after 5 years his age will be twice the sum of ages of two children find the agebof father
Answers
Answer:
Let the present age of father be x years
And, the present age of two children be y years
⠀⠀⠀⠀⠀⠀⠀⠀According to the Given Condition
Father age is 3 time the sum of the age of two children .
x = 3y ----------(i)
Again ,
After 5 years his age will be twice the sum of ages of two children .
x+5 = 2(y+10)
x+5 = 2y + 20
x -2y = 15 --------(ii)
Now, substitute the value of x = 3y in equation (ii) we get
3y -2y = 15
y = 15
Putting the value of y = 15 in equation (i) we get
x = 3×15
x = 45
- Hence, the present age of father is 45 years .
Given :-
Father age is 3 time the sum of the ages two children after 5 years his age will be twice the sum of ages of two children
To Find :-
Age of father
Solution :-
Let age of father be x
Age of two children be y
x = 3 × y
x = 3y
After 5 years
Age of father = x + 5
Age of two sons = y + 5 + 5 = y + 10
Now
x + 5 = 2(y + 10)
x + 5 = 2y + 20
x - 2y = 20 - 5
x - 2y = 15
3y - 2y = 15
y = 15
x - 2(15) = 15
x - 30 = 15
x = 30 + 15
x = 45