father and son together complete a task in 15 days. if one days work of father os 3 times one days work of his son. find the number of days required by each alone to complete the task.
Answers
Answered by
3
Step-by-step explanation:
Let the father's one day work be 3x
Son's one day work = x
Total work = 15*4x = 60x
So father does in 60x/3x = 20 days
Son does in 60x/x = 60 days .
Answered by
0
Answer:
Let F and S be the number of days required by father and son respectively.
1\F+1\S=1\15 ___(1)[Given]
Also,
F \10= S \3 _____(2)
For equation (1)&(2), we have
3\S+1\5 = 1\15
⇒S=4×15=60
Substituting the value of S in equation (2), we have
F \1= \60 \3
⇒F=20
Hence the number of days required by father and son each alone is 20 and 60 respectively.
Step-by-step explanation:
Similar questions