father is 32year more than his son's age.after 10 year father age will be twice his son age . what is the age of father
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Let the present age of son be x and present age of father be y.
1st case:present age
x+32=y ( eq 1)
2nd case:after 10yrs
2(x+10)=y+10(eq2)
using eq 1 in 2
2(x+10)=x+32+10
2x+20=x+42
2x-x=42-20
x=22
so,y=22+32(from eq 1)
=54
therefore, present age of father is 54
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