Question

Father is aged 3 times more than his son ronit. After 8 years, he would be two and a half times of ronit's age. After further 8 years, how many times would he will be of ronit's age?

Answer 1

ronit age = x yrs.

father age= 3*x

= 3x yrs.

after 8 yrs..

ronit age =x+8 yrs.

father age= 3x+8 yrs.

after further 8 yrs..

ronit age = x+8+8

= x+16yrs.

father age = 3x+8+8

= 3x+16 yrs.

no. of times father be ronit's age= 3x+16/x+16

=3 times