Father is aged 3 times more than his son ronit. After 8 years, he would be two and a half times of ronit's age. After further 8 years, how many times would he will be of ronit's age?
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ronit age = x yrs.
father age= 3*x
= 3x yrs.
after 8 yrs..
ronit age =x+8 yrs.
father age= 3x+8 yrs.
after further 8 yrs..
ronit age = x+8+8
= x+16yrs.
father age = 3x+8+8
= 3x+16 yrs.
no. of times father be ronit's age= 3x+16/x+16
=3 times
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