Math, asked by dominicasoft359, 11 months ago

Find the smallest 4 digit number divisible by 15,20,25

Answers

Answered by yash6989262
7
the smallest 4 digit no. divisible by 15,20 and 25 is 1200

because
1) 1200 divide by 15 the answer is 80
2) 1200 divide by 20 the answer is 60
3) 1200 divide by 25 the answer is 48
Answered by AnkitaSahni
2

The smallest 4 digit number divisible by 15,20,25 is 1200.

Given:

The numbers 15, 20, and 25.

To Find:

We have to find the smallest 4-digit number divisible by 15,20,25.

Solution:

This is a problem for LCM.

Let us tackle the problem.

We can simply solve this problem as follows,

We know that,

The smallest number divisible by numbers a,b,c is LCM(a,b,c,).

Therefore,

The smallest number divisible by 15,20,25 is LCM(15,20,25).

Now,

15=3×5

20=2×2×5

25=5×5

So, LCM(15,20,25) =3×2×2×5×5=300

Therefore, the smallest 4-digit number divisible by 15,20, and 25 should be a multiple of 300.

We can see that the smallest 4-digit multiple of 300 is (300×4)=1200.

Hence, the smallest 4-digit number divisible by 15,20,25 is 1200.

#SPJ3

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