Question

Father is aged three times more than his son ronit . After 8 years , he would be two and a half times of ronit's age after further 8 years how many times would he be of ronit's age ?

Answer 1

Answer:

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Answer 2

$\huge\underline\mathrm\orange{SOLUTION:-}$

Given:

• Father age is three times more than his son Ronit.
• After 8 years he would be two and a half times of Ronit's age .

Need To Find:

• After 8 years How many times would he be of Ronit's Age = ?

$\underline\mathtt\green{EXPLANATION:-}$

Suppose the Ronit and his father Age be a years.

Therefore:

$\mapsto \underline{\sf{\pink{According \ to \ the \ First \ Condition :}}}$

Father age is three times more than his son Ronit.

$\implies \sf{The \ Ronit \ Age = a \ years }$

$\implies \sf{Ronit's \ Father \ Age = 3a \ years}$

$\mapsto \underline{\sf{\pink{According \ to \ the \ Second \ Condition :}}}$

After 8 years he would be two and a half times of Ronit's age.

Therefore:

• After 8 years Ronit age = a + 8
• After 8 years Ronit's Father age = 3a + 8

$\implies \sf{3a + 8 = 2.5(a + 8)}$

$\implies \sf{3a + 8 = 2.5a + 20}$

$\implies \sf{3a - 2.5a = 20 - 8}$

$\implies \sf{0.5a = 12}$

$\implies \sf{a = \dfrac{12}{0.5}}$

$\implies \sf{a = \dfrac{120}{5}}$

$\implies \boxed{\sf{a = 24 \ years}}$

Therefore:

• Ronit age = 24 years
• Ronit's Father age = 3 x 24 = 72 years

After Furture 8 years :

$\boxed{\large{\sf{\red{After\:Further\:8\:years\:Ronit\:Age = 24 + 8 = 32 \ years}}}}$

$\boxed{\large{\sf{\red{After\:Further\:8\:years\:Ronit's\:Father\:Age = 72 + 8 = 80 \ years}}}}$

Therefore:

• After Further 8 years The Age of Father will be 2.2 times of Ronit's age.

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