Find the smallest multiple of 13 such that on being divided by 4,6,7,10 it gives remainder in each case
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13
1261
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Find the smallest multiple of 13 such that on being divided by 4,6,7,10 it gives remainder in each case
13 itself Divided by 4 , 6 , 7 & 10 gives remainder
let say Question says same reminder 1
then
4 = 2 * 2
6 = 2 * 3
7 = 7 *1
10 = 2 *5
2 *2 * 3 * 5 * 7 = 420
420a = 13b - 1
for a = 3 , b = 97
Number = 13 * 97 = 1261
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