Math, asked by hinaishaque3958, 1 year ago

Father is aged three times more than his son ronit. after 8 years, he would be two and a half times of ronit's age. after further 8 years, how many times would he be of ronit's age? 2 times 5/2times 11/4times 3times

Answers

Answered by RabbitPanda
0
let ronit age is 'x' ywears.so his father's age is 3x.
after 8 years,
therefore,ronit age is 'x+8' his fathers age is 2 and half times ronit age
so
3x+8=5/2(x+8)
..x=24 fathers age =3(24)=72
after 8 years ronit age=32 and fathers age is 80
again after 8 years ronit age=40 andfathers age is 88
therefore fathers age is 2.2 times of ronit age.
THANK YOU.
Answered by aahelegorai
0
father's age is 2.2 times of ronit 's. age if it is correct please mark me as the brainliest and thanx okk bye
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