Question

Father is aged three times more than his son ronit. after 8 years, he would be two and a halftimes of ronit's age. after further 8 years, how many times would he be of ronit's age?

Answer 1

4 times I think it may be helpful to you

Answer 2

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)

2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.

(x + 16) 24

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