Question

Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
A.2 times
B.21/2 times
C.23/4 times
D.3 times

Answer 1

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Let ronit's present age be x

the father's age will be =x+3x=4x

$after \: 8 \: years-4x+8= \frac{5}{2} (x+8)$


3x=24

x=8

$Therefore , required \: ratio \: is \: 4x+ \frac{16}{x} +16= \frac{48}{2} =2$


so option A is correct!

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Answer 2

let Ronit age is x then father age = 3x + Ronit age = 3x + x = 4x
after 8 years Ronit age = (x+8) , Father age= (4x+8)
(4x+8)=5/2(x+8) so 8x+16=5x+40
3x=24 or x = 8
so Father age = 4x = 32 , son age = 8
after 8 year Father age = 32+8=40 , son age=8+8=16
after 8 more year
Father age = 48
Son age = 24
so now age is 2 times of Ronit's age.