Question

Father is aged three times more than his son roy. After 8 years, he would be two and a half times of roy's age. After further 8 years, how many times would he be of roy's age?

Answer 1

let the son's age be x

and father's age be y

after eight years

y+8=2.5(x+8)

y=3x

on solving the 2 equations

3x+8=2.5x+20

0.5x=12

x=24

therefore y=3x=72

after 16 years

y=80 and x=32

y:x=80:32=5:2