father is five times the sum of ages of his two children .after 10 years his age will be twice the sum of ages of two children .find the age of father.
(this is related to std 10)
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Step-by-step explanation:
Let the ages of the 5 children now be x.
The age of the father now =x
Tweleve years hence the sume of the ages of the five children =x+5(12)
=x+60
Ages of the father twelve years hence =x+12
x+60=2(x+12)
x+60=2x+24
x=36
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