Father is older than his son by 25 yrs the product of their ages is 150 .Find their ages
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Answered by
1
Answer:
Step-by-step explanation:
Let's father age be x.
Son age =25-x
A to Q,
x(25-x)=150
25x-x^2=150
x^2-25x-150=0
x^2-30x+5x-150=0
x(x-30)+5(x-30)=0
(x+5)(x-30)=0
x=30/-5
We take positive as ages are always positive
So x=30
Father's age =30
Sons age=x-25
30-35
5
Answered by
0
5 is answer of your question
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