Question

Father is six times as old his son. Four years hence he be four times as old as his son at that time. Find their present ages.​

Answer 1

Given :

Let son's present age be x

Let father's present age be y

By given condition :

y = 6x

Four years hence :

(y+4) = 4(x+4)

(y+4) = (4x+16)

y-4x=16-4

y-4x=12

y-4x-12=0

substitute y=6x

6x-4x-12=0

2x-12=0

2x=12

x=12/2

x=6

y=6×6=36

Present age of son is 6 yrs

Present age of father is 36 yrs

Answer 2

Answer:

Answer

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y ... (1)

x+4=4(y+4) ...(2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years