Question

father's age 3 times of his son's age.four year ago, he is 4times his son.. find present age each

Answer 1

$\bf{\boxed{\huge{ ANSWER}}}[\tex] Let the son's age be x Father's age = 3x Four years ago Son's age = x - 4 Father's age = 3x - 4 [tex]\bf{\underline{ ACCORDING \: TO \: THE \: QUESTION}}$

$\bf{\underline{ THE \: EQUATION \: FORMED}}$

3x - 4 = 4 ( x - 4 )

=> 3x - 4 = 4x - 16

=> 4x - 3x = - 4 + 16

=> x = 12

$\bf{\underline{ ANS}}$

The son's present age is $\bf{ 12 years}$

The father's present age=

= 3 × 12 = $\bf{36 years}$

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#BE BRAINLY

@Sanskriti141