Question

Father's age is 25 years more than son. 5 years ago, son's age was one third of father's age. Find their present ages.

Answer 1

Hi friends

Here is your answer

Let the age of son is x years

Father's age is x +24 years

Five years ago,

Son's age is x - 5 years

Father's age is x+24 - 5
= x + 19 years

ATQ
$x - 5 = \frac{1}{3} (x + 19) \\ \\ 3(x - 5) = x + 19 \\ \\ 3x - 15 = x + 19 \\ \\ 3x - x = 19 + 15 \\ \\ 2x = 34 \\ \\ x = \frac{34}{2} \\ \\ x = 17$
So
Son's age is 17 years

Father's age is 17+24 = 41 years

Hope it helps you

@ MSD

Answer 2

Answer is

Let the Present age of son is x years
Father's age is x +24 years

Five years ago,

Son's age is x - 5 years
Father's age is x+24 - 5
= x + 19 years

ATQ
$x - 5 = \frac{1}{3} (x + 19) \\ \\ 3(x - 5) = x + 19 \\ \\ 3x - 15 = x + 19 \\ \\ 3x - x = 19 + 15 \\ \\ 2x = 34 \\ \\ x = \frac{34}{2} \\ \\ x = 17$


Hence
Son's Present age is 17 years

Father's Present age is
= 17+24
= 41 years

Hope it helps you

Thanks