Math, asked by tiarax98041, 1 year ago

Father's age is 3 times the sum of ages of his 2 children. After 5 five years his age will be twice the sum of ages of 2 children

Answers

Answered by peesayanusha
0
The age of father at present is 45 years.
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Answered by atharvinandgaonkar2
0

Answer:

here's your answer...

Step-by-step explanation:

let the age of father = x

and ages of his two son's = y and z

x = 3 (y+z)__________ (1)

after five years the age's will be as follows:

Father = x + 5

1 child = y + 5

2 child = z + 5

x + 5 = 2 ( y + 5 + z + 5)

x + 5 = 2 ( y + z + 10)

from (1)

x = 3 (y+ z)

3 (y + z) + 5 = 2 (y + 2) + 20

( y + z) = 15

x = 3 ( y + z)

= 3 (15)

x = 45 years

therefore, present age of father = 45 years

hope it helps you....

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