Father's age is 3 times the sum of ages of his 2 children. After 5 five years his age will be twice the sum of ages of 2 children
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The age of father at present is 45 years.
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here's your answer...
Step-by-step explanation:
let the age of father = x
and ages of his two son's = y and z
x = 3 (y+z)__________ (1)
after five years the age's will be as follows:
Father = x + 5
1 child = y + 5
2 child = z + 5
x + 5 = 2 ( y + 5 + z + 5)
x + 5 = 2 ( y + z + 10)
from (1)
x = 3 (y+ z)
3 (y + z) + 5 = 2 (y + 2) + 20
( y + z) = 15
x = 3 ( y + z)
= 3 (15)
x = 45 years
therefore, present age of father = 45 years
hope it helps you....
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