Question

father's age is 4 times of his son's age,after six years ,the father'sage will be 6 years more than the age of the son, find the age of father.​

Answer 1

Answer:

Step-by-step explanation:

LET THE SON’SAGE BE X

THEN FATHR’S AGE WOULD BE= 4X

AFTER 5 YEARS SONS AGE WILL BE 9X+5) AND FATHER’S AGE WOULD BE (4X+5)

IT IS GIVEN THAT THE FATHER WOULD BE 3 TIMES OF THE AGE OF HIS SON

THEREFORE,(4X+5)= 3(X+5)

SIMPLIFYING WE HAVE 4X-3X= 15–5= 10

HENCE SON’S AGE NOW IS 10YRS FATHERE’S AGE IS 4x X=4*10=40

AFTER 5 YRS SON

S AGE WILL BE 10+5=15 YRS

FATHER’S AGE= 40+5=45 WHICH IS 3 TIMES THE AGE OF HIS SON

Answer 2

Step-by-step explanation:

let the son's age be x

let the father's sge be y

4y=x

x-4y=0............(1)

(y+6)=(x+6)+6

y+6=6x+36

6x-y=30...........(2)

after simplifying:

you will get the answer