Question

Father’s age is 4 years more than twice the age of his son. If the sum of the ages of

father and his son is 46 years. What is the present age of son?​

Answer 1

Answer:

14

Step-by-step explanation:

First, we need to assume a variable for the son's present age, as we should assume variables for the smaller value when applicable.

Let the son's present age be 'x'.

Therefore, the father's present age is 4+2x.

ATQ,

Father's present age+son's present age= 46

Which means,

(4+2x) + x =46

4+2x+x=46

4+3x=46

3x=46-4

=42

x=42/3

= 14

Therefore, the son's present age is 14 years.

WHEN APPLICABLE, DO BOT FORGET TO WRITE "PRESENT AGE".

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Answer 2

Given :

⬤ Father age is 4 years more than twice the age of his Son .

⬤ Sum of their ages is 46 years .

To Find :

⬤ Present Age of Son .

Solution :

Let :

• Age of Son = x
• Age of Father = 2x + 4

$\sf{x+2x+4=46}$

3x + 4 = 46

3x = 46 - 4

3x = 42

x = 42/3

x = 14

Therefore , The Value of x is 21 .

Hence ,

Age of Son = x

= 14

Age of Father = 2x + 4

= 2(14) + 4

= 28 + 4

= 32

Therefore , Age of Son is 14 years and Age of Father is 32 years .