Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.
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Let the age of father be x years and sum of the ages of his children by y years.
After 5 years,
Father's age = (x + 5) years
Sum of ages of his children = (y + 10) years
From the given information, we have:
x = 3y ...(1)
and x + 5 = 2(y + 10)
x - 2y = 15 ...(2)
From (1) and (2), we have,
3y - 2y = 15 y = 15
x = 3y = 45
Father's age = 45 years
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