Question

Father was 4 times as old his son 8 years ago. Eight years hence father will be twice as old as his son .Find their present age

Answer 1

Answer:

The Father is 40 years old. The son is 16 years old.

Step-by-step explanation:

Let the age of the father= x

Let the age of the son= y

Equation 1: -

(x-8)=4(y-8)

Equation 2: -

(x+8)=2(y+8)

Solving Equation 1

x-8=4y-32

x=4y-24

Solving Equation 2

x=2y+8

Equation the solved versions of Equation 1 and 2: -

4y-24=2y+8

2y-12=y+4

y=16

x=40

Answer 2

let the father present age be=X
let the son present be =Y
A/q 8years ago
x-8 =4(y-8) (1)

after 8 yrs
X+8=2(Y+8). (2)

from 1 Nd 2