Question

fathers age is 3 times the sum of ages of this 2 children. After 5 years his age will be twice the sum of ages of 2 children.find the age of father.

Answer 1

Answer,

Let the present age of father be ‘a’ and present sum of age of sons be "b".

According to the question,

Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children.

⇒ a = 3b

a + 5 = 2(b + 10) [10 for two sons]

3b + 5 = 2b + 20

b = 15

Thus,

a = 3b = 45

Father's age =>> 45 years!

Thanks!

Answer 2

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Let the present age of father be ‘a’ and present sum of age of sons be "b".

According to the question,

Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children.

⇒ a = 3b

a + 5 = 2(b + 10) [10 for two sons]

3b + 5 = 2b + 20

b = 15

Thus,

a = 3b = 45

Father's age =>> 45 years!

HOPE SO IT WILL HELP......