Math, asked by aaryanbansal4800, 1 year ago

Find the hcf of 52 and 117 and express as 52x+117y

Answers

Answered by hukam0685
2

117 = 52 \times 2 + 13 \\ 52 = 13 \times 4  + 0 \\ hcf \: is \: 13 \\ 13 = (1)117 - 2(52) \\  =  ( - 2)52 + 1(117)
x =  - 2 \\ y = 1
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