Question

Fathers age is 5 times his son's age. 4 years back the father was 9 times older thanson.find the fathers' present age.

Answer 1

Let
Father's age=X
Son's age=Y

X=5Y---------(1) EQ

4 years back,
Father's age son's age
X-4 = (Y-4) 9
X-4 =9Y-36
X-4-9Y+36=0
X-9Y+32=0
X-9Y = -32-----------(2)EQ

Substitute
X=5Y
In eq no 2

X-9Y = -32
5Y-9Y = -32
-4Y = -32( - gets cancelled)
4Y = 32
Y = 8
X = 5Y
X=5(8)
X=40

Therefore father's age is 40 and his sons age is 8

Answer 2

Answer:

Father's age is 40 and son's age is 8

Step-by-step explanation: