Question

Fathers age is 6times sons age.4 years hence the age of father will be four times his sons age the present age of the son and father are

Answer 1

let x be fathers age and y be sons age

x=6y------(1)

4 yrs hence

(x+4) = 4(y +4)

x-4y=12 --------(2)

(1) in (2)

6y - 4y = 12

y =6

thus

x =36

hope it helps you

Answer 2

$\Large{\textbf{\underline{\underline{According\:to\:the\:Question}}}}$

Assumption

$\textbf{\underline{Present\;age\;of\;Father}}$

= p years

$\textbf{\underline{Present\;age\;of\;Son}}$

= n years

$\textbf{\underline{Situation}}$

p = 6n …(1)

$\textbf{\underline{After\;4\;years}}$

(p + 4) = 4(n + 4)

p - 4n = 12 …(2)

${\boxed{\sf\:{Substitute\;value\;of\;p\;from\;(1)\;in\; (2)}}}$

p - 4n = 12

6n - 4n = 12

2n = 12

$\tt{\rightarrow n=\dfrac{12}{2}}$

n = 6

$\textbf{\underline{Substitute\;the\;value\;in\;(1)}}$

p = 6n

p = 6 × 6

p = 36

$\Large{\boxed{\sf\:{Present\;age\;of\;Father=36\;and\;Son=6}}}$