Math, asked by 123nitinkushwapcl1eh, 1 year ago

fathers age is four time that of his son before 8 year the fathers age sixteen time that of his son find their present age

Answers

Answered by MsQueen
4
Hey mate!

Here's ur answer dear:-)
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Solution:

Let son's age be x.

Then,father’s current age will be 4x.
Now,

According to question,

That is 8 years ago,

4x- 8= 8(x- 16)

4x -8=8x- 128

128–8=8x-4x

120=4x

x=120/4

x=30

Therefore, Father's age = 4x = 4×30 = 120years.

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HOPE IT HELPS!

☺☺☺
Answered by wwefanclub078
1

Here's your answer mate:-)


Solution:

Let son's age be x.

Then,father’s current age will be 4x.
Now,

According to question,

That is 8 years ago,

4x- 8= 8(x- 16)

4x -8=8x- 128

128–8=8x-4x

120=4x

x=120/4

x=30

Therefore, Father's age = 4x = 4×30 = 120years.

HOPE IT HELPS!


MsQueen: hi
MsQueen: _No irrelevant comments_
MsQueen: hmm
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