Fatty acids with even number of carbon atoms on oxidation form
Answers
Very interesting question, as we have to find even numbered carbon atoms on oxidation forms.
While oxidizing a glucose molecule,
→ CoA - coenzyme A enters the mitochondria to combine with oxaloacetic acid, 'forming 6 carbon molecules'.
6 is a even number.
While oxidizing, other palmytoil CoA → form 16 ATP molecules along with NADH2 and FADH2.
Answer:
Fatty acids with even number of ‘carbon atoms’ on oxidation form acetyl CoA.
Explanation:
The mitochondria are the place of oxidation of ‘fatty acids’. In the primary stage-β oxidation-the unsaturated fats experience oxidative evacuation of progressive two-carbon units as acetyl-CoA, beginning from the carboxyl finish of the acyl chain.
For instance, the 16-carbon unsaturated fat palmitic acid (palmitate at pH 7) experiences seven goes through this oxidative succession, in each pass losing two carbons as acetyl-CoA. Toward the finish of seven cycles the last two carbons of palmitate (initially C-15 and C-16) are left as acetyl-CoA.