Question

faye had a piece of ribbon.after using 3/8 meter for her headband ,she had 1/4 meter left. how many meters of ribbon did she have at first?

Answer 1

Given

• Faye had a piece of ribbon.
• Ribbon used ⇒ 3/8 meter
• Ribbon left ⇒ 1/4 meter

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To Find

• Meters of ribbon she had at first.

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Solution

Meters of ribbon used ⇒ 3/8 meters

Meters of ribbon left ⇒ 1/4 meters

Total ribbon she had = Meters of ribbon used + Meters of ribbon left

Total ribbon she had = $\sf \dfrac{3}{8} + \dfrac{1}{4}$

⇒ $\sf \dfrac{3}{8} + \dfrac{1}{4}$

LCM of 8 and 4 is 8.

⇒ $\sf \dfrac{3}{8} + \dfrac{1}{4}$

⇒  $\sf \dfrac{3\times 1 }{8\times 1 } + \dfrac{1\times 2}{4\times 2}$

⇒  $\sf \dfrac{3}{8} + \dfrac{2}{8}$

⇒  $\sf\dfrac{5}{8}$

∴ Faye had 5/8 meters of ribbon at first.

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Answer 2

★᭄ꦿ᭄Answer★᭄ꦿ᭄

Given

Faye had a piece of ribbon.

Ribbon used ⇒ 3/8 meter

Ribbon left ⇒ 1/4 meter

__________________________

To Find

Meters of ribbon she had at first.

__________________________

Solution

Meters of ribbon used ⇒ 3/8 meters

Meters of ribbon left ⇒ 1/4 meters

Total ribbon she had = Meters of ribbon used + Meters of ribbon left

Total ribbon she had = $\sf \dfrac{3}{8} + \dfrac{1}{4}$

⇒ $\sf \dfrac{3}{8} + \dfrac{1}{4}$

LCM of 8 and 4 is 8.

⇒ $\sf \dfrac{3}{8} + \dfrac{1}{4}$

⇒  $\sf \dfrac{3\times 1 }{8\times 1 } + \dfrac{1\times 2}{4\times 2}$

⇒  $\sf \dfrac{3}{8} + \dfrac{2}{8}$

⇒  $\sf\dfrac{5}{8}$

∴ Faye had 5/8 meters of ribbon at first.

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