Question

$\fbox{${\fbox{${\underline{HOTS}}$}}$}$

$\huge\tt\red{ | Question:- | \gamma }$

Find
$1 + \frac{ {1}^{2} + {2}^{2} }{2!} + \frac{ {1}^{2} + {2}^{2} + {3}^{2} }{4!} + \frac{ {1}^{2} + {2}^{2} + {3}^{2} + {4}^{2} }{4!} + ... \infty = \frac{b}{6} e. \: Find \: b$

Gd mrng EVERYBODY
PLZ ans this question​

Answer 1

Both the denominators cannot be 4! as you have given. Check the question properly and repost directly from textbook.

Answer 2

The question is wrong however. I have posted the solution of the correct question.

Correct question :- https://brainly.in/question/37847722?utm_source=android&utm_medium=share&utm_campaign=question