Math, asked by pankti12, 1 year ago

fctorize 2
2 \sqrt{3x { }^{2} }  - 5x -  \sqrt{3}

Answers

Answered by rohitkumargupta
9
HELLO DEAR,

2√3X² - 5X - √3

=> 2√3X² - 6X + X - √3 = 0

=> 2√3x(x-√3) + 1(x-√3)

=> (2√3x+1)(x-√3) =0

=> X = -1/2√3

Or

X = √3




I HOPE ITS HELP YOU DEAR,
THANKS
Answered by TheLifeRacer
1
Hey !!

2√3x² - 5x -√3

=> 2√3x² -6x+x -√3 [by using splitting middle term rule of quadratic equation ]

=> 2√3x² - 2 ×√3*√3 +x-√3

=> 2√3(x -√3) +1(x -√3)

=> (2√3+1)(x -√3) is the factor of given equation

and if you find the zero of equation .

(2√3x+1) (x-√3 ) =0

(2√3x+1) =0
x = -1/2√3
and , (x -√3 ) =0
x =√3

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Hope it helps you !!!.

@Rajukumar111
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