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HELLO DEAR,
2√3X² - 5X - √3
=> 2√3X² - 6X + X - √3 = 0
=> 2√3x(x-√3) + 1(x-√3)
=> (2√3x+1)(x-√3) =0
=> X = -1/2√3
Or
X = √3
I HOPE ITS HELP YOU DEAR,
THANKS
2√3X² - 5X - √3
=> 2√3X² - 6X + X - √3 = 0
=> 2√3x(x-√3) + 1(x-√3)
=> (2√3x+1)(x-√3) =0
=> X = -1/2√3
Or
X = √3
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
1
Hey !!
2√3x² - 5x -√3
=> 2√3x² -6x+x -√3 [by using splitting middle term rule of quadratic equation ]
=> 2√3x² - 2 ×√3*√3 +x-√3
=> 2√3(x -√3) +1(x -√3)
=> (2√3+1)(x -√3) is the factor of given equation
and if you find the zero of equation .
(2√3x+1) (x-√3 ) =0
(2√3x+1) =0
x = -1/2√3
and , (x -√3 ) =0
x =√3
******************,******
Hope it helps you !!!.
@Rajukumar111
2√3x² - 5x -√3
=> 2√3x² -6x+x -√3 [by using splitting middle term rule of quadratic equation ]
=> 2√3x² - 2 ×√3*√3 +x-√3
=> 2√3(x -√3) +1(x -√3)
=> (2√3+1)(x -√3) is the factor of given equation
and if you find the zero of equation .
(2√3x+1) (x-√3 ) =0
(2√3x+1) =0
x = -1/2√3
and , (x -√3 ) =0
x =√3
******************,******
Hope it helps you !!!.
@Rajukumar111
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