Question

FeBr3 + H2SO4 gives Fe2(SO4)3 + HBr
balance this equation​

Answer 1

Answer:

2FeBr3 + 3H2SO4 → Fe2(SO4)3 + 6HBr

Explanation:

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Answer 2

The correct answer is:

2$FeBr_{3}$ + 3$H_{2} SO_{4}$     ------------->   $Fe_{2} (SO_{4})_{3}$ + 6$HBr$

1. To balance a chemical equation, we will first count the number of atoms in reactants and products.

2. On the products side, Fe has two atoms while on the reactants side, Fe has one atom. To balance, we will place a 2 in front of FeBr3.

2$FeBr_{3} + H_{2} SO_{4}$     --------------->     $Fe_{2} (SO_{4})_{3} + HBr$

3. Now, on the reactants side, Br has 6 atoms while on the products side, Br has only one atom. To balance, we will place a 6 in front of HBr.

2$FeBr_{3} + H_{2} SO_{4}$     --------------->     $Fe_{2} (SO_{4})_{3} +$ 6$HBr$

4. Now, on the reactants side, H has 2 atoms while on the products side, H has 6 atoms. To balance, we will place a 3 in front of H2SO4.

2$FeBr_{3} +$ 3$H_{2} SO_{4}$     --------------->     $Fe_{2} (SO_{4})_{3} +$ 6$HBr$

4. The SO4 atom is balanced on both sides. Hence, the chemical equation is balanced on both sides.