fencing the compound of a house cost rupees rupees 4930 the rate is rupees 85 per metre find the perimeter of the compound if the breadth is 10 metre find its length
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Answered by
8
Perimeter=cost/rate=4930/85=58m
perimeter=2 (l+b)
58=2 (l+10)
58=2l+20
58-20=2l
2l=38
l=38/2
length=19metre
perimeter=2 (l+b)
58=2 (l+10)
58=2l+20
58-20=2l
2l=38
l=38/2
length=19metre
Answered by
8
perimeter of compound = total cost of fencing / cost for fencing per metre
= 4930/85=58 m
perimeter = 58=2(l+b)
(l+b)= 58/2=29
l+ 10 = 29m
length = 29—10 =19m
hope it help you..
thank you
Happy New Year
I request u to mark this answer as brainliest.....
= 4930/85=58 m
perimeter = 58=2(l+b)
(l+b)= 58/2=29
l+ 10 = 29m
length = 29—10 =19m
hope it help you..
thank you
Happy New Year
I request u to mark this answer as brainliest.....
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