Question

Fend three consecutive Even numbers
such that
sum of first and third is 40
​

Answer 1

Step-by-step explanation:

let x, x+2,x+4 are three consecutive even numbers

x+x+4=40

2x=40-4=36

x=18

x+2=18+2=20

x+4=18+4=22

three consecutive even numbers are 18,20,22

Answer 2

ANSWER :-

• Numbers are 18 , 20 and 22.

CORRECT QUESTION :-

• Find three consecutive even numbers such that sum of first and 3rd number is 40.

GIVEN :-

• There are 3 consecutive even numbers
• Sum of 1st and 3rd number is 40.

TO FIND :-

• The three consecutive even numbers.

SOLUTION :-

Even number is the multiple of 2.

So , let the three consecutive even numbers be (2x) , (2x+2) and (2x+4)

Here ,

• 1st number → 2x
• 2nd number → 2x + 2
• 3rd number → 2x + 4

We know that sum of 1st and 3rd number is 40.

→ (2x) + (2x + 4) = 40

→ 2x + 2x + 4 = 40

→ 4x + 4 = 40

→ 4x = 40 - 4

→ 4x = 36

→ x = 36/4

→ x = 9

Numbers are :-

• (2x) = 2(9) = 18
• (2x+2) = 2(9) + 2 = 20
• (2x+4) = 2(9) + 4 = 22

Hence , the three consecutive even numbers are 18 , 20 and 22 whose sum of 1st and 3rd number is 40.

VERIFICATION :-

Sum of 1st and 3rd number should be 40.

18 + 22 = 40

40 = 40 (verified)

MORE TO KNOW :-

• Consecutive numbers are written as (x) , (x+1) , (x+2) and so on.
• Consecutive odd numbers are written as (2x+1) , (2x+3) , (2x+5) and so on.