Question

FeS₂+O₂⇒Fe₂O₃+SO₂ Balance the given Redox Reaction. Explain. please

Answer 1

Answer:

Explanation:FeS2 + O2 ---> Fe2O3 + SO2

Now, 

In reactant side,

Fe = 1

S = 2

O = 2

In product side, 

Fe = 2

S = 1

O = 3+2 = 5

None is balanced 

Let us take Fe.

In reactant side 1 and product side 2.

Thus, add 2 before Fe in reactant side.

Now we have, 

2 FeS2 + O2 ---> Fe2O3 + SO2

Now, Fe balanced.

In reactant side,

S = 4

O = 2

In product side,

S = 1

O = 5

Now, let us balance S.

We have 4 S in reactant side and 1 S in product side.

Add 4 before S in product side 

Now we have the equation,

2 FeS2 + O2 ---> Fe2O3 + 4 SO2

Now, Fe and S are balanced.

Now, let us balance O.

In reactant side we have 2 and in product side we have 11

O is odd in product side. As balancing is hit and trial method let us use one trick. Whenever we get stuck like this, make the odd thing even.

So, add 2 before Fe2O3.

Now,

2 FeS2 + O2 ---> 2 Fe2O3 + SO2 

Now, we have 2 Fe in product side and 4 Fe in reactant side. So, add 2 before FeS2. 

Thus, 2+2 FeS2 = 4 FeS2

Now, 

4 FeS2 + O2 ---> 2 Fe2O3 + 4 SO2

Now, we have 8 S in reactant side and 4 S in product side. Add 4 in reactant side.

4 + 4 SO2 = 8 SO2

Now,

4 FeS2 + O2 ---> 2 Fe2O3 + 8 SO2

We have 2 O in reactant side and 22 O in product side.

So, 22 O = 2 × 11 = 22 O.

Therefore, add 11 before O2.

Now the equation is,

4 FeS2 + 11O2 ---> 2 Fe2O3 + 8 SO2

Now, let us check 

In reactant side,

Fe = 4

S = 8 

O = 22

In product side,

Fe = 4

S = 8

O = 22

Hence, balanced 

_____________________________

The balanced equation:

4 FeS2 + 11O2 --->2 Fe2O3 + 8 SO2