Question

FeSO4 solution mixed with (NH4)2SO4 solution in 1:1 molar ratio gives the test of Fe2+ ion but CuSO4 solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu2+ ion. Explain why?

Answer 1

Answer:

◦•●◉✿ Aɴsᴡᴇʀ: FᴇSO4 ᴅᴏᴇs ɴᴏᴛ ғᴏʀᴍ ᴀɴʏ ᴄᴏᴍᴘʟᴇx ᴡɪᴛʜ (NH4)SO4. Iɴsᴛᴇᴀᴅ, ᴛʜᴇʏ ғᴏʀᴍ ᴀ ᴅᴏᴜʙʟᴇ sᴀʟᴛ, FᴇSO4. ... CᴜSO4 sᴏʟᴜᴛɪᴏɴ ᴍɪxᴇᴅ ᴡɪᴛʜ ᴀϙᴜᴇᴏᴜs ᴀᴍᴍᴏɴɪᴀ ɪɴ 1 : 4 ᴍᴏʟᴀʀ ʀᴀᴛɪᴏ ғᴏʀᴍs ᴛʜᴇ ᴄᴏᴍᴘʟᴇx ᴡɪᴛʜ ᴛʜᴇ ғᴏʀᴍᴜʟᴀ [Cᴜ(NH3)]SO4 ɪɴ ᴡʜɪᴄʜ ᴛʜᴇ ᴄᴏᴍᴘʟᴇx ɪᴏɴ, [Cᴜ(NH3)4]2+ ᴅᴏᴇs ɴᴏᴛ ᴅɪssᴏᴄɪᴀᴛᴇ ᴛᴏ ɢɪᴠᴇ Cᴜ2+ ɪᴏɴs. ✿◉●•◦

Answer 2

Answer:

Feso4 and (NH4)So 4 will form Molhr's salt or ammonium Iron (II),[(NH4)2Fe (So4)2.6H2O] , which is double salt. But CuSo4 with ammonia form a complex salt

Explanation:

we know that double can dissociate into simple ion in it's aqueous solution but complex salt cannot dissociate completely in it's aqueous solution as the complex ion remains unchanged in aqueous.

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