Fibd the ap in whuch the fourthterm is 9 and sum of its sixth and thirteenthterm is 40
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Answer:t4=9, 9=a+3d............(1)
t6+t13=40
a+5d+a+12d=40
2a+17d=40..........(2)
From 1 and 2
a+3d=9
2a+17d=40
d=2
a=3
Step-by-step explanation: AP is 3 ,5 ,7,9,11,13.......
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