Math, asked by princedas261, 11 months ago

fidivded smallest number which when divided by 66,77 and 88 leaves 3 as remainder​

Answers

Answered by rohanpv27
0

Answer:

1851

Step-by-step explanation:

first find prime factors for 66,77,88

then the LCM would be 1848

since we want remainder as 3 add 3 to 1848.

we get 1851 as the required number which when divided by 66,77,88 leaves the remainder 3.

we can also verify it by division.

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