fifty children went skating. Three of the children wore black skates and 7/10 of them wore blue skates . How many wore neither blue nor black skates?
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Blue skates=7/10×50=35
black skates=3(atq)
therefore, number of children with neither of the skates= 50-(35+3)
= 50-38
=12
black skates=3(atq)
therefore, number of children with neither of the skates= 50-(35+3)
= 50-38
=12
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