Question

Fifty three integers are multa multiplied together, what will be results its of their foroduct, if​

Answer 1

Answer:

Total number of cases obtained by taking multiplication of only two numbers out of 100=

100

C

2

Out of 100(1,2,...,100) given numbers, there are the numbers 3,6,9,12...,99

which are 33 in numbers such that when any one of them is multiplied with any of the remaining 67 numbers

as any two of these 33 are multiplied, the resulting product is divisible by 3.

Then the pairs of numbers whose product is divisible by 3=

33

C

1

×

67

C

1

+

33

C

2

Hence, the required probability=

100

C

2

33

C

1

×

67

C

1

+

33

C

2

=

4950

2739

=0.55

Answer 2

o.55

Answer:

o.55

Step-by-step explanation:

the main answer is o.55