Question

Fig. 10.4
In Fig. 10.5. if AOB is a diameter of the circle
and AC = BC, then LCAB is equal to:
(B) 60°
a
a o
А
B.
(A) 300
O
(C) 900
DX45​

Answer 1

Answer:

It's (d) 45°

Step-by-step explanation:

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