Question

Fig. is attached below.
Que. Is to prove how ∠ abc = ∠acb

Answer 1

Answer:

The Value of x is 80°.

Step-by-step explanation:

Given :

The triangle is an = Isosceles triangle

One angle is = 50°

To find :

The value of x

Solution :

$\sf{\overline{AB}} = \sf{\overline{AC}}$ .....[Given]

As the triangle is an Isosceles triangle ;

According to the property, an isosceles triangle has two equal angles. The ones opposite the two equal sides are equal angles.

Angles opposite to the equal sides are $\angle$ ACB and $\angle$ ABC

$\therefore$ $\angle$ ACB = $\angle$ ABC

⇒ $\angle$ ABC = 50°

$\rule{300}{1.5}$

★ Value of x =

We have the Value of two angles of the triangle, the third angle =

According to the Angle Sum property of triangle, sum of all angles in a triangle is 180°.

⇒ $\angle$ ACB + $\angle$ ABC + $\angle$ BAC = 180°

⇒ 50° + 50° + x = 180°

⇒ 100° + x = 180°

⇒ x = 180° - 100°

⇒ x = 80°

$\therefore$ The Value of x is 80°.

Answer 2

$\huge\sf{Answer:-}$

Prove how ABC = ABC

so,

[ABC = 50° is equal to ABC = 50°]

AB = AC

we have to find the value of x

Using Angle Sum Property

$\sf = ACB + ABC + BAC = 180° \\ </p><p>\sf = 50° + 50° + x = 180° \\ </p><p>\sf = 100° + x = 180° \\ </p><p>\sf= x = 180° - 100° \\ </p><p>\bf= x = 80°$

Hence, 80° is the value of x