Question

Fig of merit of 2 galvanometer of resistance 100ohms and 50ohms are 10^(-8)A/div and2×10^(-5)A/div respectively . In which case voltage sensitivity is more.

Answer 1

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Answer 2

Given:

Resistances are

$R_{1}=100$ Ω

$R_{2}=50$ Ω

The two divisions are

$1\ div=10^{-8}\ A$

$1\ div=2\times10^{-5}\ A$

To Find: The case in which sensitivity is more

Solution:

Use the formula of ohm's law $V=I\times R$

Case-I for Resistance $R_{1}$

$1\ div=100\times10^{-8}$

$=10^{-6}\ V$

Case-II for Resistance $R_{2}=50$ Ω

$1\ div=50\times2\times10^{-5} \\=10^{-3}\ V$

Case-I has more sensitivity.