Question

Figure (28-E2) shows a copper rod joined to a steel rod. The rods have equal length and equal cross sectional area. The free end of the copper rod is kept at 0°C and that of the steel rod is kept at 100°C. Find the temperature at the junction of the rods. Conductivity of copper = 390 W m−1°C−1 and that if steel = 46 W m−1°C−1.
Figure

Answer 1

Answer:jdfLyoh0yh f7fld goflty6w.

Explanation:83ifin .gighkffo gusvlb ificv offogg hphotktg otrwaiu.

Answer 2

The temperature at the junction of the rods is $T=10.55^{\circ} \mathrm{C} \approx 10.6^{\circ} \mathrm{C}$

Explanation:

$\mathrm{K}_{1}=390 \mathrm{W} \mathrm{m}^{-10} \mathrm{C}^{-1}$

$\mathrm{K}_{2}=46 \mathrm{Wm}^{-10} \mathrm{C}^{-1}$

Let q1=rate of heat flow in copper

     q2=rate of heat flow in steel

As both the rods are in series so heat flow is equal $\mathrm{q}_{1}=\mathrm{q}_{2}$

  $\frac{T-0}{R_{1}}=\frac{100-T}{R_{2}}$

  $\frac{A K_{1} T}{l}=\frac{A K_{2}(100-T)}{l}$

  $T=\frac{K_{2} 100}{\left(K_{1}+K_{2}\right)}$

By putting the values in above equation we get

  $T=10.55^{\circ} \mathrm{C} \approx 10.6^{\circ} \mathrm{C}$