Question

Figure (31-Q3) shows two capacitors connected in series and joined to a battery. The graph shows the variation in potential as one moves from left to right on the branch containing the capacitors.
(a) C1 > C2
(b) C1 = C2
(c) C1 < C2
(d) The information is not sufficient to decide the relation between C1 and C2.

Answer 1

Answer:

By applying various rules of calculating the oxidation number of the desired element in a compound, the oxidation number of each metallic element in its compound is as follows:

HAuCl4 → Au has 3

Tl2O → Tl has 1

FeO → Fe has 2

Fe2O3 → Fe has 3

CuI → Cu has 1

CuO → Cu has 2

MnO → Mn has 2

MnO2 → Mn has 4

Therefore, these compounds may be represented as: HAu(III)Cl4, Tl2(I)O, Fe(II)O, Fe2(III)O3, Cu(I)I, Cu(II)O, Mn(II)O, Mn(IV)O2

Explanation:

Answer 2

(c) So, the capacitance is C1 < C2.

Explanation:

• Please note, region AB shows the potential difference across capacitor C1 and region CD shows the potential difference across capacitor C2.
• We can see from the graph that region AB is greater than region CD. Hence, the potential difference across capacitor C1 is greater than that across capacitor C2.  
• Therefore, Capacitance, C = QVQV
• C1 < C2  (Q remains the same in series connection)