figure 6.40 angle X = 60° ,angle XYZ = 54° , if Y and Z are the bisectors of angle XYZ and angle XZY respectively of ∆XYZ find angle OZY and angle YOZ
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when angle x and y are given we can determine angle z
x+y+z=180
62+54+z=180
z=180-116
z=64
now we know that line OY is bisector of y
so angle oyz=54/2 = 27
line OZ is bisector of z
so angle ozy=62/2 = 31
as we know oyz and ozy we can find O
oyz+ozy+o=180
27+31+O=180
o=180-58
O=122
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