Question

Figure below depict air enclosed in a cylinder by an air tight piston. The piston has been pushed as shown In figure (ii) so that the air occupies one-third of the length of the cylinder it previously occupied

Answer 1

Answer:

Explanation:

Let the piston be displaced by small amount X and the increase in pressure be △p.  

Initial pressure   P1=P0+AMg

Volume               V1=V0

Final pressure  P2=P1+△p

Volume             V2=V0−△V,△V=Ax

Applying Poisson's equation

P1V1γ=P2V2γ

P1V1γ=(P1+△p)(V0−△V)γ

=P1V0γ(1+P1△P)(1−V0△V)γ

1=(1+P1△P)(1−γ

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