Figure below gives the x-t plot of a particle in one dimensional motion. Three different equal intervals of time are shown. In which interval is the average speed greatest, and in which is it the least? Give the sign of average velocity for each interval.
Attachments:
Answers
Answered by
5
Hii friend,
# Answer-
- Maximum avg speed- Interval 3
- Minimum avg speed- Interval 2
- Positive velocity- Intervals 1 & 2
- Negative velocity- Interval 3
# Explanation-
- The average speed of a particle in the x-t graph is obtained from the slope of the graph in a particular interval of time.
In the graph
- Slope is maximum in interval 3, hence avg speed is maximum.
- Slope is minimum in interval 2, hence avg speed is minimum.
- As the slope is positive in these intervals 1 & 2, sign of average velocity is positive in both intervals
- As slope is negative in interval 3, sign of avg speed is negative there.
Hope that is useful...
# Answer-
- Maximum avg speed- Interval 3
- Minimum avg speed- Interval 2
- Positive velocity- Intervals 1 & 2
- Negative velocity- Interval 3
# Explanation-
- The average speed of a particle in the x-t graph is obtained from the slope of the graph in a particular interval of time.
In the graph
- Slope is maximum in interval 3, hence avg speed is maximum.
- Slope is minimum in interval 2, hence avg speed is minimum.
- As the slope is positive in these intervals 1 & 2, sign of average velocity is positive in both intervals
- As slope is negative in interval 3, sign of avg speed is negative there.
Hope that is useful...
Answered by
1
According to given graph :
So in the given graph : Average speed is greater in interval 3 because its slope is greater.
Average speed is least in interval 2 because slope is minimum.
Reason :
As we know that Average Speed = Slope of X- Graph in that time interval.
Average velocity is positive in interval 1 and 2 and negative in interval 3.
Similar questions