Question

Figure below shows a man standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 m s⁻². What is the net force on the man? If the coefficient of static friction between the man's shoes and the belt is 0.2, up to what acceleration of the belt can the man continue to be stationary relative to the belt? (Mass of the man = 65 kg)

Answer 1

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Since the man is Stationary
The accleration of belt = Acceleration of Man

Net force on the man
➖F =ma

=65×1

=65N

Coefficient of friction f' =0.2

Limiting friction =f'mg

For the man to be stationary with respect to belt accelerating with ′a' ′of belt

▶ma'=f'mg ( cancel out m to m )

▶a' = f' g

▶=0.2×9.8

▶=1.96ms−2 Ans



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Hope this helps . . . . . .

Answer 2

Hey mate,

# Answer-
a) F = 65 N
b) a = 2 m/s^2

# Explaination-
# Given-
m = 65 kg
a = 1 m/s^2
g = 10 m/s^2

# Solution-
a) For a man standing stationary -
Net force on man = Force on belt
F = m×a = 65×1 = 65 N
Net force on man is 65 N.

b) For a man to remain stationary -
Net force on man <= Frictional force
ma' <= μmg
a' <= μg
a' <= 0.2×10
a' <= 2 m/s^2
For a man to remain stationary maximum acceleration of belt can be 2 m/s^2.

Hope that was useful...