Question

Figure below shows the position-time graph of a body of mass 0.04 kg. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the body? What is the magnitude of each impulse?

Answer 1

Hii dear,

◆ Physical context-
We can compare the graph with that of ball rebounding between two adjacent walls distanced by 2 cm.

● Calculations -
# Time between impulses -
We can see from the graph that the ball changes it's direction every 2 s. Hence, time betn two impulses is 2 s.

# Magnitude of impulse-
Here as ball rebounds,
u = s/t = -v
Impulse = change in momentum
I = m(u-v)
I = m(u+u)
I = 2ms/t
I = 2×0.04×0.02/2
I = 8×10^-4 kgm/s
Magnitude of impulse is 8×10^-4 kgm/s.

Hope that helps you...

Answer 2

hi buddy

here is your answer

$time \: between \: 2 \: impulses$

$velocity = \frac{d}{t}$

$\frac{2 \times {10}^{ - 2} }{2}$

$= 0.01 \frac{m}{s}$

$initial \: momentum =mu = 0.04 \times {10}^{ - 2} \frac{kgm}{s}$

$final \: moment \: mv = 0.04 \times {10}^{ - 2} \frac{kgm}{s}$

$change \: in \: momentum \: = \frac{0.08}{times}$

${10}^{ - 2} \frac{kgm}{s}$

hope it helps you

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#Sibi ❤