Question

Figure show a brick of weight 2 kgf and dimensions 20 cm x 10 cm x 5 cm placed in three different positions on the ground. Find the pressure exerted by the brick in each case. 20 cm 10 cm 10 cm 10 cm 5 cm 20 cm 5 cm 20 cm​

Answer 1

Explanation:

We know that P=

A

F

, here A=effective area

In first case , P=

A

mg

=

0.1×0.2

2×10

=1000Pa

In second case , P=

0.05×0.1

2×10

=4000Pa

In third case , P=

0.05×0.2

2×10

=2000Pa

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